4. In the accompanying diagram of AGBD, points M and N are midpoints of GB and BD.
Solve for x, and find the length of MN and GD.
B
M
N
X + 23
G
D
5x + 13

my answer is$ 12

step-by-step explanation:

because 15 -2=12

the correct answer is 5 6 and 7

ranks (& how to earn them):

-beginner (needs at least 0 points & 0 brainliest answers)

- hand (needs at least 100 points & 0 brainliest answers)

-ambitious   (needs at least 250 points & 0 brainliest answers)

-virtuoso (needs at least 500 points & 5 brainliest answers)

-expert   (needs at least 1,000 points & 10 brainliest answers)

-ace (needs at least 3,000 points & 15 brainliest answers)

-genius   (needs at least 15,000 points & 50 brainliest answers)

how to award brainliest:

you must wait until 2 people answer to award brainliest. i'm pretty sure that it should be next to the "" and "comments" buttons.  

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.