Alexis has a piece of red paper that is 4 centimeters wide. its length is twice its width. she glues a piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters. how many square centimeters of red paper will be visible on top?

It is given:Alexis has a piece of red paper that is 4 centimeters wide. Its length is twice its width .If  length is 4cm then width = 4x2= 8cm.

Area of red paper= length x width = 4x8=32 square cm.

Alexis glues a piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters.

Area of blue paper= 3x7=21 square cm.

Area of  red paper  that will be visible on top =32-21= 11 square cm.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.