What is the volume, in cubic cm, of a cylinder with a height of 11cm and a base radius of 9cm, to the nearest tenths place?

Step-by-step explanation:

I’m not good at round but the answer without the rounding is 2799.16

2799.2 cm cubed

Step-by-step explanation:

h\hspace{3px}=\hspace{3px}11\hspace{30px}r\hspace{3px}=\hspace{3px}9

h=11r=9

identify variables

V=

V=

\,\,\pi r^2h

πr

2

h

use volume of a cylinder formula

V=

V=

\,\,\pi(9)^2(11)

π(9)

2

(11)

substitute variables into formula

V=

V=

\,\,2799.15905435

2799.15905435

multiply

V=

V=

\,\,2799.2\text{ cm}^3

2799.2 cm

3

round to the nearest tenths place

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.