A rectangles base is 2in. Shorter than twice its height. The rectangles area is 40in^2. Find it's dimensions.

5 in by 8 in

Step-by-step explanation:

Given that :

Area, A of rectangle = 40 in²

Let

height = x

Base = 2x - 2

Area of rectangle = L * B

40 = x * (2x - 2)

40 = 2x² - 2x

2x² - 2x - 40 = 0

x² - x - 20 = 0

x² - 5x + 4x - 20 =0

x(x - 5) +4(x - 5) = 0

x - 5 = 0 or

x + 4 = 0

x = 5 or x = - 4

X cannot be negative

X = 5

Height = 5

Base = 2*5 - 2 = 8

answer: the answer is 127 degrees

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b