BE and CE are twoequal alltitudes of triangle ABC using RHS congurence rule prove that triangle ABC is isoloes

The answer is below

Step-by-step explanation:

BE and CF are two equal altitudes of triangle ABC using RHS congruence rule prove that triangle ABC is isosceles.

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

The RHS congruence rule states that if the hypotenuse and one leg of one triangle is equal to the hypotenuse and leg of another triangle; then the two triangles are equal. Two triangles are equal if they have three equal angles and three equal sides.

We have right angle triangles BEC and BFC

BE = CF (given)

CB = BC (both triangles have the same hypotenuse)

Hence ΔBEC = ΔBFC (RHS congruence rule)

Therefore; ∠BCE = ∠FBC (congruence theorem)

Since two angles of triangle ABC are equal (∠B = ∠C), therefore triangle ABC is an isosceles triangle and AB = AC

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

35 is an outlier

step-by-step explanation: