Mathematics, 10.02.2021 01:10 9Time
Solve for x: 256^{x-1}= 256 x−1 = \,\,4^{2x+2} 4 2x+2
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On #16 : explain how factoring a trinomial, ax^2+ bx+ c, when a does not equal 1 different from factoring a trinomial when a = 1.
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Solve for x: 256^{x-1}= 256 x−1 = \,\,4^{2x+2} 4 2x+2...