Write an equation for the line perpendicular to y = 2x – 5 that contains (–9, 6)

Write an equation for the line 
perpendicular to y = 2x - 5 that contains (-9,6).
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The given line has slope = 2
Any line perpendicular to it must have slope = (-1/2)

Form:
y = mx + b
Solve for "b":
6 = (-1/2)(-9) + b
6 = (9/2) + b

b = 3/2

Equation:
y = (-1/2)x + (3/2)

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