En una pension de perros hay tres perros que pesan 20kg 10kg y otro 5kg si se contempla que 70kg de alimento dura 2 meses¿que cantidad de alimento le toca a cada perro ? Problema de proporcionalidad inversa

40kg

20kg

10kg

Step-by-step explanation:

The computation of the food each one is getting as follows

Total weights of all dogs

= 20 kg + 10 kg + 5kg

= 35 kg

And, the food is 70 kg

So, each one is getting

for 20 kg

= 70 ÷ 35 × 20

= 40 kg

For 10 kg

= 70 ÷ 35 × 10

= 20 kg

And, for 5 kg

= 70 ÷ 35 × 5

= 10 kg

step-by-step explanation:

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5