Using either substitution or elimination method, solve the system of equations that consists of 8x+y= -16 and -3x+y=-5 Your solution will be a coordinate of integers. ​

x= -1

y= -8

Step-by-step explanation:

Solve for y in 8x + y = -16

y = -16 - 8x

Substitute y = -16 - 8x into -3x + y = -5

-11x - 16 = -5

Solve for x in -11x - 16 = -5

x = -1

Substitute x = -1 into y = -16 - 8x

y = -8

Therefore,

x= -1

y= -8

(-1, -8)

Step-by-step explanation:

SUBSTITUTION METHOD:

Solve for y in the first equation by subtracting 8x from both sides.

Substitute this value for y into the second equation.

Remove the parentheses and simplify.

Combine like terms.

Add 16 both sides of the equation.

Divide both sides of the equation by -11.

Substitute this value for x into either equation (I'm using the first equation).

Multiply and simplify.

Add 8 to both sides of the equation.

ELIMINATION METHOD:

Subtract the second equation from the first equation to "cancel" the y-variable.

Divide both sides of the equation by 11.

Substitute this value for x into either equation (I'm using the second equation).

Multiply and simplify.

Subtract 3 from both sides of the equation.

The solution to this system of equations is (-1, -8).

picture below

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3