Assume that x = x(t) and y = y(t). Let y = x^2 + 6 and
dx/dt=4 when x=1
Find dy/dt when x = 1

= 8

Step-by-step explanation:

Given:

x = x(t) and y = y(t)

Let y = x² + 6

By differentiating the given equation with respect to t,

Since, when x = 1

[By substituting the values of and x = 1]

= 8

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )