A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 S

Complete Question:

A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 Seconds.

a. what acceleration is imparted to the paper?

b. if the mass of the paper is 0.003 kg, what force does the boxer exert on it?

c. how much force does the paper exert on the boxer?

a. Acceleration = 454.55m/s².

b. Force = 1.36N

c. Force = -1.36N

Step-by-step explanation:

Given the following data;

Final velocity = 20m/s

Time = 0.044 seconds.

Since the paper is at rest, we know that it's initial velocity is equal to 0m/s.

a. To find acceleration;

Mathematically, acceleration is given by the equation;

Substituting into the equation, we have;

Acceleration = 454.55m/s²

b. To find the force exerted by the boxer;

Mass = 0.003kg

Force = mass * acceleration

Force = 0.003 * 454.55

Force = 1.36N

c. To find the force exerted by the paper;

According to Newton's third law of motion which states that, for every action there is an equal and opposite reaction. Therefore, the paper exerts an equal but opposite force on the boxer.

Force = -1.36N

for ex: the reciprocal of 3/4 is 4/3. it is the opposite.

reciprocal definition:

a mathematical expression or function so related to another that their product is one; the quantity obtained by dividing the number one by a given quantity.

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: