2. ABCD is a square and P, Q are the midpoints of BC, CD respectively. If AP = a and AQ = b, find in terms of a and b, the directed line segments (i) AB, (ii) AD, (iii) BD and (iv) AC.

The answer is below.

Step-by-step explanation:

A square is a quadrilateral (has four sides and four angles) in which all the sides are equal. Also all the angle of a square are equal and measure 90°. The diagonals of a square are equal.

In square ABCD:

AB = BC = CD = AC

Given that  P, Q are the midpoints of BC, CD respectively. If AP = a and AQ = b.

a) In triangle ABP:

BC = AB (all sides of a triangle are equal)

BP = 1/2 (BC) = 1/2(AB) = 0.5AB

Using Pythagoras theorem:

AB² + BP² = AP²

substituting:

AB² + (0.5AB)² = a²

AB² + 0.25AB² = a²

1.25AB² = a²

AB² = a² / 1.25

AB² = 0.8a²

AB = √(0.8a²)

AB = a√0.8

b) In triangle ADQ:

AD = CD (all sides of a triangle are equal)

DQ = 1/2 (CD) = 1/2(AD) = 0.5AD

Using Pythagoras theorem:

AD² + DQ² = AQ²

substituting:

AD² + (0.5AD)² = b²

AD² + 0.25AD² = b²

1.25AD² = b²

AD² = b² / 1.25

AD² = 0.8b²

AD = √(0.8b²)

AD = b√0.8

c) In triangle ABD, Using Pythagoras theorem:

AB² + AD² = BD²

Substituting:

0.8a² + 0.8b² = BD²

But AB = AD (all sides of a triangle are equal). Hence AB = AD = 0.8a² = 0.8b²

BD = √(0.8a² + 0.8b²)

BD = √(1.6a²)     0.8a² = 0.8b²

BD = a√1.6

D) AC = AD (diagonal are equal)

AC = √(0.8a² + 0.8b²)

AC = √(1.6b²)     0.8a² = 0.8b²

AC = b√1.6

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240