Suppose someone gives you 6 to 1 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win 6 dollars if you succeed and lose 1 dollar if you fail. What is the expected value of this game to you. What can you expect if you play 200 times

0.75 ;

150

Step-by-step explanation:

Probability of rolling two even numbers :

{1, 2, 3, 4, 5, 6}

P(even) = 3 / 6 = 1/2

From a roll of 2 dice :

P(even) * P(even) = 1/2 * 1/2 = 1/4 = 0.25

P(not even) = 1 - 1/4 = 3/4

X : 6 - 1

P(x) 0.25 0.75

Expected value :

Σx*p(x) = (6*0.25) + (-1 * 0.75)

= 1.50 - 0.75

= 0.75

If 200 games are played :, n = 200

Expected value * n

0.75 * 200

= 150

its 8

step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all