Consider a population consisting of 600 individuals with unique IDs: 001, 002, . . . , 600. Use the following string of random digits to select a simple random sample of 5 individuals. List the IDs of the individuals selected for your sample. 7 2 8 1 2 1 8 7 6 4 4 2 1 2 1 5 9 3 7 8 7 8 0 3 5 4 7 2 1 6 5 9 6 8 5 1

121 ; 442 ; 593; 547 ; 216

Step-by-step explanation:

Using the string of random digits given below :

7 2 8 1 2 1 8 7 6 4 4 2 1 2 1 5 9 3 7 8 7 8 0 3 5 4 7 2 1 6 5 9 6 8 5 1

Range of ID's : 001, 002, . . . , 600

Since, length of Unique ID = 3

and it does not exceed 600 ; we choose each consecutive 3 length string from the random digit given which does not exceed 600

7 2 8; 1 2 1; 8 7 6; 4 4 2; 1 2 1; 5 9 3; 7 8 7; 8 0 3; 5 4 7; 2 1 6; 5 9 6; 8 5 1

Stings which do no exceed 600:

121 ; 442 ; 593; 547 ; 216 ; 596

Randomly selected ID's could by any 3 digit string from the string data given which does not exceed 600

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110

4+3x is the answer

hope you got it