This probability distribution shows the typical grade distribution for a Geometry course with 35 students. HELLLPPP PLSSS

P(A, B or C) = 6/7 or 0.8571

Step-by-step explanation:

From the image, we have the frequency for each grade as;

Grade A = 5

Grade B = 10

Grade C = 15

Grade D = 3

Grade F = 2

We want to find the probability that a student earns a grade of A, B or C.

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

Thus;

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

Step-by-step explanation:

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

now we round to the hundredths place

0.8571 ⇒ 0.86

step-by-step explanation:

answer for #1 is c

answer for #2 is d

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