Infinite Algerba 1
18.2x10^-1=
19.2x10^5=
20.804x10^2=
21. 2.66x10^4=
22. 1...
Mathematics, 08.02.2021 04:10 mathisaqeosmw
Infinite Algerba 1
18.2x10^-1=
19.2x10^5=
20.804x10^2=
21. 2.66x10^4=
22. 1.5x10^-2=
23. 7.75x10^-1=
24. 8.3x10^7=
25.9.5x10^7=
26.1.7x10^7=
27.0.910^-3=
28.38x10^2=
29.7.5x10^5=
30.4x10^0=
31.8.4x10^5=
32.4x10^-5=
Answers: 3
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Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
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