What is the area of △JKL in square units? KJL is a triangle. The angle J is 94 degree and the angle L is 26 degree. Side JK is 24 and JL is 41.

426.07 square units

Step-by-step explanation:

Recall that for a triangle whose angles are A,B,C  with corresponding sides a, b, c, the area G of the triangle may be computed as

G = 1/2 ab Sin C

or

G = 1/2 bc Sin A

or

G = 1/2 ac Sin B

Going by this, recall that the sum of angles in a triangle is 180 hence

94 + 26 + K = 180

120 + K = 180

Subtract 120 from both sides

K = 180 - 120

K = 60 degrees

Given that JK = 24 and JL = 41

G = 1/2 * 24 * 41 Sin 60

= 426.07 square units

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.