Can someone tell me if my answer is correct (and correct it if it's not)? What is the area of an EQUALATERAL triangle with a side length of 6? I'm getting 5.19615242, is this right?

15.59.

Step-by-step explanation:

The altitude of equilateral triangle bisects the base

So 1/2 base = 3.

Altitude of the triangle is found from Pythagoras theorem:

= sqrt(6^2 - 3^2)

= sqrt27

Area = 1/2 base * altitude

=  3 * sqrt27

= 15.59

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

312312

step-by-step explanation: