Suppose the half-life of a certain radioactive substance is 20 days and there are 50g present initially. a)
Write an equation that models this situation.
b)
How much radioactive substance is remaining after 12 days?
c)
Find the time when there will be 1g of the substance remaining.

a)   10(5g + 2r)   weight loss over time

b)   20/12 = 1.66667 = 50 / 1.67 = 29.999 gm = 5(6g -1/50)  or  5(5 + g) = 30g

c) 30g = 12 days = 3/5   therefore 5/5 -3/5 = 2/5  = 2/5 x 50 (g) = 20g in 8 days lost

8/20 = 0.4  loss each day 50g - 0.8g = 20-2 = 18 days.

Step-by-step explanation:

the distance from any point on the parabola to the focus is the exact same as the distance from that point to the directrix.

if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (:

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answer: d.) the total number of protons and neutrons is 15

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