Find an equation of the straight line that is perpendicular to y=2x+1 and passes through the point (-2,5)

y = -1/2x + 4

Step-by-step explanation:

to answer this question you need to find the slope and the y-intercept

to find the slope of a line that is perpendicular to another line you take the opposite and reciprocal of the slope of the first line

in this case the slope of the initial line is 2; therefore, the opposite reciprocal is -1/2

knowing slope ('m') = -1/2 and having the point (-2, 5) can give us the y-intercept of the new line; we start with:

y = mx + b  and then plug the values in so find the y-intercept ('b')

5 = (-1/2)(-2) + b

5 = 1 + b

b = 4

put it all together:  y = -1/2x + 4

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b