To prepare for a lab experiment, Ted is making a solution that uses two types of concentrations of HCI ( hydro boric acid) 80 ml of 50% HCI solution, and 120 mlL of 20% HCI solution. What is the HCI concentration of the mixes solution

32%

Step-by-step explanation:

50% of the first solution is HCL, so it has

80 ml x 50% = 80 ml x 0.5 = 40 ml of HCL

Similarly the second solution has 20% of HCL, so

120 ml x 20% = 120 ml x 0.2 = 24 ml of HCL

The combined solution will have 40 ml + 24 ml = 64 ml of HCL.

The total volume of the 2 solutions is 80 ml + 120 ml = 200 ml.

We can now calculate the concentration of HCL in the mixed solution, by dividing the volume of HCL by the total volume of the solution,

64 ml / 200 ml = 0.32 = 32%

answer: -8.2562234e+13

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3