The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for hours. The Thompson family's sprinkler was used for hours. There was a combined total output of of water. What was the water output rate for each sprinkler if the sum of the two rates was per hour

This question s incomplete, the complete question is;

The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.

There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour  

The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

Step-by-step explanation:

Given the data in the question;

let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively

so

x + y = 55  equ1

x = 55 - y qu2

also

15x + 30y = 1050

x + 2y = 70 equ3

input equ2 into equ3

(55 - y) + 2y = 70

- y + 2y = 70 - 55

y = 15

input value of y into equ1

x + 15 = 55

x = 55 - 15

x = 40

Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer