100 POINTS! The midpoint of GH is M(4, -3). One endpoint is G(-2, 2). Find the coordinates of endpoint H.

(10, -8)

Step-by-step explanation:

solution given:

G(x1,y1)=(-2,2)

H(x2,y2)=(x,y)

Mid point M(a,b)=(4,-3)

we have

(a,b)=((x1+x2)/2,(y1+y2)/2)

(4,-3)=((-2+x)/2,(2+y)/2)

comparing corresponding value

4=(-2+x)/2

8+2=x

x=10

again

(2+y)/2=-3

2+y=-6

y=-6-2

y=-8

So coordinates of H is (10,-8).

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3