Simplify the expression below.
12b + 86 + 5b
0 25 + b
O 25(3b)
25b
3b

(1): "^-5" was replaced by "^(-5)". 3 more similar replacement(s)

STEP

1

:

Equation at the end of step 1

                    ((25•(b-1))•(c-3))

 (((12•(b4))•(c-6))•——————————————————)•((2•5b(-5))•c)

                     ((15•(b3))•(c4))

STEP

2

:

Equation at the end of step

2

:

                    ((25•(b-1))•(c-3))

 (((12•(b4))•(c-6))•——————————————————)•(2•5b(-5)c)

                       ((3•5b3)•c4)  

STEP

3

:

Equation at the end of step

3

:

                    (52b(-1)•c(-3))

 (((12•(b4))•(c-6))•———————————————)•(2•5b(-5)c)

                       (3•5b3c4)  

STEP

4

:

           52b(-1)c(-3)

Simplify   ————————————

            (3•5b3c4)  

Dividing exponential expressions :

4.1    b(-1) divided by b3 = b((-1) - 3) = b(-4) = 1/b4

Dividing exponential expressions :

4.2    c(-3) divided by c4 = c((-3) - 4) = c(-7) = 1/c7

Dividing exponents:

4.3    52   divided by   51   = 5(2 - 1) = 51 = 5

Equation at the end of step

4

:

                      5  

 (((12•(b4))•(c-6))•—————)•(2•5b(-5)c)

                    3b4c7

STEP

5

:

Equation at the end of step

5

:

                         5  

 (((22•3b4) • c(-6)) • —————) • (2•5b(-5)c)

                       3b4c7

STEP

6

:

Canceling Out :

6.1    Canceling out b4 as it appears on both sides of the fraction line

Dividing exponential expressions :

6.2    c(-6) divided by c7 = c((-6) - 7) = c(-13) = 1/c13

Canceling Out:

6.3      Canceling out  3  as it appears on both sides of the fraction line

Equation at the end of step

6

:

  20

 ——— • (2•5b(-5)c)

 c13

STEP

7

:

Multiplying exponents:

7.1    22  multiplied by  21   = 2(2 + 1) = 23

Multiplying exponents:

7.2    51  multiplied by  51   = 5(1 + 1) = 52

Dividing exponential expressions :

7.3    c1 divided by c13 = c(1 - 13) = c(-12) = 1/c12

Final result :

  200

 —————

 b5c12

Step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

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step-by-step explanation: