What are the coordinates of the point in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6?

The coordinates of the point P  in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6 will be:

Step-by-step explanation:

Let P be the point.

As the point P is in the directed line segment from (-2,-8) to (5,-1) into the ratio of 1 to 6

i.e.

(x₁, y₁) = (-2,-8)

(x₂, y₂) = (5,-1)

Rise = y₂ - y₁ = -1 - (-8) = -1 + 8 = 7

Run = x₂ - x₁ = 5 - (-2) = 5 + 2 = 7

1 : 6 ratio means the point P lies at

Thus,

rise for P = 7 × 14% = 1

run for P =  7 × 14% = 1

Thus, coordinates of P will be:

x = -2 + 1 = -1

y = -8 + 1 = -7

Thus,

The coordinates of the point P  in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6 will be:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

24

step-by-step explanation: