BRO CAN SOMEONE PLEASE HELP ME THIS TEST IS A MAJOR GRADE I CAN HELP YOU WITH SOMETHING BUT PLEASE HELP ME WITH THIS The length, l , of a rectangle is 3 cm longer than twice the width, w. The perimeter of the rectangle is 66 cm.

Which system of linear equations could be used to find the length and width of the rectangle?
A. l = 3w + 2
2l + 2w = 66

B. l = 3w + 2
l + w = 66

C. I= 2w + 3
l + w = 66

D. l = 2w + 3
2l + 2w = 66

The system of linear equations that could be used to find the length and width of the rectangle will be:

l = 2w + 3 cm  

2w + 2l = 66

Hence, option D is correct.

Step-by-step explanation:

Let the width of the rectangle be = w cm

Given that the length, l, of a rectangle is 3 cm longer than twice the width, w.

Thus, the length of the rectangle be:

l = 2w + 3 cm  

We know that the perimeter of the rectangle is:

P = 2w + 2l

Given that the perimeter of the rectangle = P = 66 cm

so substitute P = 66 in P = 2w + 2l

P = 2w + 2l

66 = 2w + 2l

Therefore, the system of linear equations that could be used to find the length and width of the rectangle will be:

l = 2w + 3 cm  

2w + 2l = 66

Hence, option D is correct.

answer: was that a question or answer?

step-by-step explanation:

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5