The function y=f(x) is graphed below. What is the average rate of change of the function f(x) on the interval -8 ≤ x ≤ -1?

The average rate of change of the function is: 0

Step-by-step explanation:

The function y = f(x) is graphed below.

From the graph it is clear that:

at x = -8, the value of f(-8) = -10

at x = -1, the value of f(-1) = -10

We have to determine the average rate of change of the function f(x) on the interval -8 ≤ x ≤ -1.

so

at x₁ = -8, f(x₁) = f(-8) = -10

at x₂ = -1, f(x₂) = f(-1) = -10

Using the formula to determine the average rate of change of the function f(x) on the interval -8 ≤ x ≤ -1.

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]  

                      = [f(-1) - f(-8) ] / [-1-(-8)]

                      = [-10 - (-10)] / [-1+8]

                      = [-10 + 10] / 7

                      = 0 / 7

                      = 0

Therefore, the average rate of change of the function is: 0

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)