The point Q has coordinates (2,3) The point R has coordinates (a, b)
A line perpendicular to QR is given by the equation 5x + 2y = 9
Find an expression for b in terms of a. W

b= (2a+11)/5

Step-by-step explanation:

5x + 2y = 9

2y=9-5x

y= 9/2 - 5x/2

slope, m1= -5/2

for perpendicularity, m1 × m2 = -1

slope for QR= m2=

m2 is 2/5

5(b-3)=2(a-2)

5b-15=2a-4

5b=2a-4+15

5b= 2a+11

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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