Triangle M N O is shown. Angle O N M is a right angle. Angle N O M is 40 degrees and angle L M N is 50 degrees. Given right triangle MNO, which represents the value of cos(M)?

StartFraction O N Over M N EndFraction
StartFraction M N Over M O EndFraction
StartFraction O N Over M O EndFraction
StartFraction M N Over O N EndFraction

Given:

In triangle MNO, angle ONM is a right angle. Angle NOM is 40 degrees and angle LMN is 50 degrees.

To find:

The value of cos(M).

Solution:

In a right angle triangle,

Draw a diagram using the given information.

In triangle MNO, angle ONM is a right angle so its opposite side MO is the hypotenuse. For vertex M, MN is the base of the triangle. So,

Therefore, the correct option is B.

mr. graef told us it is 13 pints

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)