3. A cell phone plan costs $0.20 cents per minute. Lisa has budgeted $35 a month for her cell phone. How
many minutes Lisa can use each month?

175 minutes or 2 hrs and 55 minutes

Step-by-step explanation:

35÷0.20 and you'll get 175

i think it’s 175 minutes

Step-by-step explanation: i think it’s 175 minutes because if you have 35 dollars for a month then you can set up an equation. 3500 = 20x. i converted the 35 dollars to cents just to make it easier but you could also do 35 = .20x. then just solve the equation by dividing both sides by 20 or .20 and you get 175 i’m not entirely sure tho sorry if i’m wrong hope this helped :D

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

i would say b) is your answer

sorry if im wrong

step-by-step explanation: