The product of 3 and a number equals the sum of 16 and a number.

The numbers can be either -8,-7,-6, or 6, 7, 8.

n(n−1)(n+1)=16(n−1+n+n+1)  

⟹n(n2−1)=16×3n  

⟹n(n2−1)n=48nn  

⟹(n2−1)−48=48−48  

⟹n2−49=0  

⟶(n−7)(n+7)=0  

n  can be  7  or  −7 , so the numbers can be either  −8,−7,−6  

Or

6,7,8

Step-by-step explanation:

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.