Point A is (-9,-3) and is translated 4 left and 2 down. Where is A' at?

A translation maps point A(3,7)A(3,7)A, left parenthesis, 3, comma, 7, right parenthesis to point A'(6,-2)A

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(6,−2)A, prime, left parenthesis, 6, comma, minus, 2, right parenthesis. Let's determine what translation this is.

Solution

Step 1: Horizontal shift. AAA is shifted 333 units to the right because (6)-(3)=\tealD{+3}(6)−(3)=+3left parenthesis, 6, right parenthesis, minus, left parenthesis, 3, right parenthesis, equals, start color #01a995, plus, 3, end color #01a995.

Step 2: Vertical shift. AAA is shifted 999 units down because (-2)-(7)=\maroonD{-9}(−2)−(7)=−9left parenthesis, minus, 2, right parenthesis, minus, left parenthesis, 7, right parenthesis, equals, start color #ca337c, minus, 9, end color #ca337c.

The AAA is mapped onto A'A

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A, prime under a translation by \langle \tealD{3},\maroonD{-9} \rangle⟨3,−9⟩open angle, start color #01a995, 3, end color #01a995, comma, start color #ca337c, minus, 9, end color #ca337c, close angle.

Step-by-step explanation:

To isabellacouch0382

Step-by-step explanation:

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b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b