Lines a and b represent a system of linear equations. Line a passes through the points (1,3) and (3,1). Line b passes through the point (-1,0) Which statement must be true?
1) If line b passes through the point (-2,1) then there are infinitely many solutions to the system of equations because the slopes of the lines are the same.
2) If line b passes through the point (0,1) then there is more than one solution to the system of equations because the lines are perpendicular.
3) If line b passes through the point (1,3) then there are infinitely many solutions to the system of equations because line a also passes through the point (1,3)
4) If line b passes through the point (1,-2) then there is no solution to the system of equations because the lines are parallel.

step-by-step explanation:

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step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

i dont know the answer but here's a picture of a dog