How many molecules of SO2 gas would occupy 4.15 L at STP?

The number of molecules of SO₂ gas that would occupy a volume of 4.15 L at STP is 1.1153125 × 10²³ molecules

Step-by-step explanation:

The given parameters for the SO₂ gas are;

The volume of the gas = 4.15 L

The condition of the gas = Standard Temperature, and Pressure, STP

The molar volume = The volume occupied by one mole of a gas at STP = 22.4 L

Therefore, we have;

22.4 L = The volume occupied 1 mole of gas

∴ The number of moles in 1 L of gas = 22.4 L/22.4 of gas = 1/22.4 moles of gas

The number of moles in 4.15 L of gas = 4.15 × 1/22.4 moles = 83/448 moles

∴ The number of moles of SO₂ in 4.15 L of SO₂ = 83/448 moles of SO₂.

The number of molecules in one ole of a substance is given by Avogadro's number, = 6.02 × 10²³ molecules

1 mole of a substance contains 6.02 × 10²³ molecules

83/448 moles of substance contains 83/448 × 6.02 × 10²³ = 1.1153125 × 10²³ molecules

Therefore, the number of molecules in 83/448 moles of SO₂ = 1.1153125 × 10²³ molecules

Therefore, the number of molecules of SO₂ gas that would occupy 4.15 L at STP = 1.1153125 × 10²³ molecules.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

probably the last option

step-by-step explanation: