-x+y+z=1, x-y+z=2, x+y-z=1

(3/2, 1, 3/2)

Step-by-step explanation:

Given the simultaneous equation

-x+y+z=1... 1

x-y+z=2 ... 2

x+y-z=1 3

Add equation 1 and 2;

-x+x + y - y + z + z = 1+2

0 + 0 + 2z = 3

2z = 3

z = 3/2

Add equation 2 and 3

x+x = 2 + 1

2x = 3

x = 3/2

Substitute x = 3/2 and z = 3/2 into 3

From 3;

x+y-z = 1

3/2 + y - 3/2 = 1

y + 0 = 1

y = 1

Hence the solution (x, y, z) is (3/2, 1, 3/2)

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

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