1.What is the frequency of the sinusoidal graph? 2.Graph h(x)=7sinx- help me graph it please
SOMEONE PLEASE HELP WITH THE CORRECT ANSWERS GIVING A 100 POINTS FOR IT

1. " second picture"

2. The graph of h(x) is shown below.

Step-by-step explanation:

The given function is

h(x)=7\sin xh(x)=7sinx

The general form of sine function is

f(x)=a\sin(bx+c)+df(x)=asin(bx+c)+d

Where, a is amplitude, b is period, c is phase shift and d is vertical shift.

So, the amplitude of the given function is 7, period is 1, phase shift is 0 and vertical shift is 0.

It means the minimum value of function is -7 and maximum value is 7.

Put x=0 in the given function.

h(x)=7\sin (0)=7(0)=0h(x)=7sin(0)=7(0)=0

Put x=-\frac{\pi}{2}x=− 2ππ in the given function.

h(x)=7\sin (-\frac{\pi}{2})=-7(1)=-7h(x)=7sin(−2π )=−7(1)=−7

Put x=\frac{\pi}{2}x= 2π in the given function.

h(x)=7\sin (\frac{\pi}{2})=7(1)=7h(x)=7sin( 2π )=7(1)=7

Therefore the points on the function are (0,0), (-\frac{\pi}{2},-7),(\frac{\pi}{2},7)(− 2π ,−7),( 2π,7) .

The graph of function is shown below.

"Hope this helps"

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this