Solve for a and b pls and ty

Solve through trigonmetry:

Im writing the 3 root as 3 because my computer doesnt have the root...though i'll add it in the calculator

For b

Tan-theta= P/B

tan45= 3/b

btan45=3

b=3/tan45

b= 1.73

For a

Sin-theta= P/H

sin45= 3/a

asin45=3

a= 3/sin45

a= 2.45

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

b. hoped i'm right lol

step-by-step explanation: