Find the equation for the parabola with vertex (1,4) that passes through the point (3,8)

y=(x-1)²+4

Step-by-step explanation:

The equation for a parabola in vertex form is y=a(x-h)²+k

(h,k) represents the vertex of the parabola

The value of "a" represents the stretch or compression factor

Since the vertex is (1,4) this means (h,k)=(1,4). To find the value of a, we plug in (3,8) as (x,y) in the equation:

y=a(x-h)²+k

8=a(3-1)²+4

8=a(2)²+4

8=a(4)+4

8=4a+4

4=4a

a=1

Since a=1 the parabola doesn't compress or stretch. This means that our final equation is y=(x-1)²+4

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl