subject
Mathematics, 04.02.2021 01:00 sustaitaj2022

A firecracker is shot upward off a balcony that is 10 feet above the ground with an initial velocity of v feet per second. The firecracker reaches a maximum height of 30.25 feet at 1.125 seconds after being shot upward. The formula for the vertical motion of an object is h(t) = \frac{1}{2} at {}^{2} + vt + sh(t)=21at2+vt+s
where the gravitational constant, a, is -32 feet per second, and h(t) is the height in feet modeled as a function of time, t.

The initial velocity of the firecracker is
A. 12
B. 27
C. 36
feet per second

The time when the firecracker reaches the ground is
A. 1.25
B. 2
C. 2.5
seconds

The correct answers are C and C I just need to understand why.
Thanks!

ansver
Answers: 2

Other questions on the subject: Mathematics

image
Mathematics, 21.06.2019 17:00, savannahsims4750
If i have a 24 in loaf of bread and i cut it into two pieces one 9 in how long was the other
Answers: 2
image
Mathematics, 21.06.2019 18:00, puppylover72
Solve this and show you’re work step by step ! -5 3/4+3h< 9 1/4 -
Answers: 1
image
Mathematics, 21.06.2019 19:30, sb6998
In need of in the diagram, ∠abc is a right angle. ∠dbc = 30°27'40". find the measure of ∠abd.
Answers: 1
image
Mathematics, 21.06.2019 23:50, sainijasdeep27
Write the standard form of an equation with (see picture below)
Answers: 2
You know the right answer?
A firecracker is shot upward off a balcony that is 10 feet above the ground with an initial velocity...

Questions in other subjects:

Konu
Mathematics, 11.10.2020 23:01
Konu
Mathematics, 11.10.2020 23:01