Pls help me this is 7th grade math

I cannot see the entire question for two of them, however angle 6 is 84 degrees and angle 5 is 96 degrees.

Step-by-step explanation:

Parallel lines crossed by a transversal form special pairs of angles. Angle 84 is vertical to angle 2. Vertical angles are equal. Angle 2 is also 84. Angle 84 and angle 4 are corresponding angles. They are equal, so angle 4 is 84. Angles 4 and 6 are vertical angles. Vertical angles are equal. This means angle 6 is also 84. Now for the rest of the missing angles. Linear pairs of angles are supplementary (sum to 180). 84 and angle 1 are a linear pair. We know they have to sum to 180. 180 - 84= 96. Angle 1 is 96. If angle 1 is 96, then we know that angle 3 is 96 because they are vertical angles. If angle 3 is 96 then we know angle 7 is 96 because they are corresponding angles. And finally angle 5 is 96 because it’s vertical to angle 7. ( there are many different ways to solve this ex: linear pairs sum to 180,

Same side interior angles sum to 180, same side exterior angles sum to 180. Alternate interior angles are equal, Alternate exterior angles are equal, corresponding angles are equal, vertical angles are equal)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

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step-by-step explanation: