△KJL~△WJX. Identify the coordinates of X and the scale factor.

PLZ help

X(−64/3, 0); 8/3

Step-by-step explanation:

To find the coordinates of the point X, first find the scale factor for a dilation of two similar triangles in the coordinate plane

To determine the scale factor, set up a ratio of the lengths of two corresponding sides of the triangles.

Use the Distance Formula d=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√ to find the length of the sides JK and JW.

Point J is the origin. Thus, the coordinates of the point J are (0,0).

It is given in the figure that the coordinates of the point K are (0,6).

To find JK, substitute x1=0, x2=0, y1=0, and y2=6 into the distance formula.

JK=(0−0)2+(6−0)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=62‾‾√=6

The length of JK is 6.

It is given in the figure that the coordinates of the point W are (0,16).

To find JW, substitute x1=0, x2=0, y1=0, and y2=16 into the distance formula.

JW=(0−0)2+(16−0)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=162‾‾‾‾√=16

The length of JW is 16.

To determine the scale factor, set up a ratio of the lengths of two corresponding sides, JW and JK, of the triangles.

JWJK=166=83

The scale factor is 83.

To find the coordinates of the point X multiply the coordinates of the point L by the scale factor.

It is given in the figure that the coordinates of the point L are (−8,0).

X(−8⋅83,0⋅83)=X(−643,0)

The coordinates of the point X are (−643,0).

The figure shows the same triangles K J L and W J X as in the beginning of the task. Point X is at minus 64 thirds, zero.

Therefore, the coordinates of X is (−643,0) and the scale factor is 83.

answer: true

step-by-step explanation:

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.