In a survey of 250 people concerning how they obtain information about current events, 70 people read a newspaper each day, 130 watch news on television each day, and 30 read a newspaper and watch the news on television each day. If a person is selected at random from the group surveyed, what is the (empirical) probability that the person does not either read a newspaper or watch the news on television each day?

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

bdhfnfhjffjkfjfjfjjf

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

i believe its the last graph