Carrie needs to take a cab uptown and only has y dollars. The cab company charges a flat fee of $2.25 plus $0.55 per mile. If Carrie has $12.52 and she finds a cab company with the same flat fee that only charges $0.45 per mile, what is the maximum number of miles she will be able
to travel, to the nearest tenth of a mile?
what is the equation?

The maximum number of miles she will be able  to travel, to the nearest tenth of a mile is less than or equals to 22.8 miles.

She needs to take a cab and has y dollars. The company charges a flat rate of $2.25 plus $0.55 per mile. Therefore the equation will be

y = 2.25 + 0.55x

where

x = number of miles travelled.

Now she has $12.52 and she finds a cab company with the same flat rate and only charges $0.45 per mile. The maximum number of miles she will be able to travel to the nearest tenth of mile can be calculated below:

2.25 + 0.45x ≤ 12.52

x = number of miles travelled.

0.45x ≤ 12.52 - 2.25

x ≤ 10.27 / 0.45

x ≤ 22.8222222222

x ≤ 22.8 miles

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infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions