5. There are 29 students available to represent the upperclassmen at a fair. 13 are juniors and 16 are seniors. What is the probability, as a percent that
a senior and junior will be chosen?

senior and junior? that would be a perfect 100%, 29/29

Step-by-step explanation:

Unless I'm incorrect, this question states the probability of BOTH a senior AND junior being chosen, which would be 100% or again, 29/29

The probability that a senior will be chosen is 55.2% or 16/29. And The probability a Junior will be chosen is 44.8% or 13/29.

Explanation:

Since the total students are 29. I put the 29 as the denominator and converted these fractions into percentages to find my answer.

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet