Write a function in the form y = mx + b for the line that passes through the points (2, 4) and (6, 16).

y = 3x -2

Step-by-step explanation:

y = 3x - 2 (see below)

Step-by-step explanation:

First, you want to find the slope of this line.

The slope formula is:

       y2 - y1

m =

       x2 - x1

Your points are (2, 4) and (6, 16), so plug them in:

       16 - 4

m =

       6 - 2

       12

m = = 3

       4

So slope is 3.

Now, to find the y-intercept (b), you have to use either one of the points and plug in the values into the slope-intercept formula:

y = mx + b

I'll use the point (2, 4):

4 = 3 (2) + b

Simplify for b:

4 = 6 + b

-2 = b

b = -2

Now just plug in your b and m values:

y = 3x - 2

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: