Factor 4x^2-4x-8
Please help

4x² - 4x - 8 can be factored into 4(x - 2)(x + 1)

Step-by-step explanation:

First, we can factor out 4, as all terms are divisible by that:

4x² - 4x - 8

= 4(x² - x - 2)

Now we need to find two numbers that are are factors of -2, but add up to -1.  -2 and 1 meet that condition, so let's split the middle term into those coefficients:

=4(x² + x - 2x - 2)

= 4( x(x + 1) - 2(x - 1) )

= 4(x - 2)(x + 1)

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