WILL MARK BRAINLIEST! THANK YOU An equilateral triangle has a side length of 40.

Another side of the same triangle measures 3x + y.
The third side of the same triangle measures 4x - 2y.
What are the values of x and y that would keep the triangle equilateral?

x=12, y=4

Step-by-step explanation:

All the sides are the same length.

3x+y = 40

4x-2y = 40

Eliminate y terms: divide second equation by 2 and add to first equation

2x-y = 20

3x+y = 40

5x = 60

x = 12

y = 40-3x = 4

We know that all sides of the equilateral triangle is equal.

Given :---

An equilateral triangle has a side length of 40.

Another side of the same triangle measures

3x + y.

The third side of the same triangle measures

4x - 2y.

According to the above problem, the equation are

3x+y=40(i) and 4x-2y=40(ii)

Divide the equation (ii) by 2, we get

2x-y=20(iii)

Now solving for x and y we get,

3x+y=40(i)

2x-y=20(iii)

5x =60

x=60/5

x=12

Putting the value of x in equation in equation (iii) we get

24-y=20

y=24-20

y=4

The values of x and y that would keep the triangle equilateral are 12 and 4 respectively.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.