PLEASE HELP!! WILL MARK BRAINLIEST! THANK YOU An equilateral triangle has a side length of 40.

Another side of the same triangle measures 3x + y.
The third side of the same triangle measures 4x - 2y.
What are the values of x and y that would keep the triangle equilateral?

x=12

y = 4

Step-by-step explanation:

3x + y = 4x - 2y

x = 3y

y= 1/3x

3x + y = 40             3x + y = 40

3(3y) + y = 40         3x + (1/3x) = 40

9y + y =40              10/3x = 40

10y = 40                  x = 12

y= 4

We know that all sides of the equilateral triangle is equal.

Given :---

An equilateral triangle has a side length of 40.

Another side of the same triangle measures

3x + y.

The third side of the same triangle measures

4x - 2y.

According to the above problem, the equation are

3x+y=40(i) and 4x-2y=40(ii)

Divide the equation (ii) by 2, we get

2x-y=20(iii)

Now solving for x and y we get,

3x+y=40(i)

2x-y=20(iii)

5x =60

x=60/5

x=12

Putting the value of x in equation in equation (iii) we get

24-y=20

y=24-20

y=4

The values of x and y that would keep the triangle equilateral are 12 and 4 respectively.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.