What are the solutions of each equation?
a. x2 + 4 = 4
b. x2 + 16 = 0
c. x2 − 49 = 0

a. x=0

b x=-8

c x=49/2

Step-by-step explanation:

a. x2+4=4

subtract 4 from both sides

x2=0

multiply

2x=0

divide by 2

x=0

b x2 + 16 = 0

multiply

2x+16=0

subtract both sides by 16

2x=-16

divide by 2

x=-8

c  x2 − 49 = 0

multiply

2x-49=0

add 49 to both sides

2x=49

divide both sides by 2

x=49/2

a. X= 0

b. X= undefined or X=4i

c. X= + or - 7

Step-by-step explanation:

a. x² + 4 = 4

when 4 goes to the other side by negative sign it will cancel the other 4. at they equal in magnitude and opposite in sign.

then x² = 0 , where √x²=√0 , finally x=0

b. x² + 16 = 0

16 goes to other side by negative sign too

x² = -16 , where √x²=√-16 , finally x= undefined

due to the negative sign under thr square root.

at √-1 = i then x can be 4i

c. x² - 49 = 0

-49 go to the other side by positive sign

x² = 49 , where √x² = √49 , finally x= + or - 7

where negative sign is neglected at even power

example:

(-7)²=(7)²

11) obtuse

13)right

15) acute