For which value of x is the relation not a function? \ (0,1),(x,0),(3,5)\ 2,6\ }

Please check the explanation.

Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

In our case, we need to determine the value of x so that we can have repeated or duplicated inputs or x-values because duplicated inputs mean the relation would not be a relation.

Given

{(0, 1), (x, 0), (3, 5), (2, 6)}

Now, if we put x = 3, the relation would become:

{(0, 1), (3, 0), (3, 5), (2, 6)}

Here, x = 3 is repeated twice, and we can not have duplicated inputs as there should be only 1 output for each input.

Therefore,

For the value of x = 3, the relation would not be a function.

Note: The same can be said about the values of x = 0, or x = 2 because then the the dupilcated values be x = 0 or x = 2 respectively.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: